To solve this problem, we can simplify the expression by applying the properties of integer exponents.
Starting with the given expression: (2−3⋅93)−429⋅9−10
First, we can simplify the exponent (2−3⋅93) by subtracting the exponents: 2−3 ⋅ 9^3 = 2−3 ⋅ 729
Then, we can simplify the exponent 429⋅9−10 by multiplying: 429 ⋅ 9−10 = 429 ⋅ (1/9^10)
The equivalent expression with positive exponents would be:
(2−3⋅93)−429⋅9−10 = 2−3 ⋅ 729 − 429 ⋅ (1/9^10)
Therefore, the correct answer is D. 2−7⋅9−129⋅9−10 (Start fraction 2 superscript negative 7 baseline times 9 superscript negative 1 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction).