Question

Use the image to answer the question.

An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.

Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′ ?

(1 point)
Responses

(2, 0)
left parenthesis 2 comma 0 right parenthesis

(10, 4)
left parenthesis 10 comma 4 right parenthesis

(2, 12)
left parenthesis 2 comma 12 right parenthesis

(6, 0)

Answer 1

[AI-generated answer — Bot GPT 3.5]

The coordinates of P' are (4 + 2, 6 - 6), which simplifies to (6,0). Therefore, the correct answer is option (D) (6,0).

Answer 2

are you sure

Answer 3

[AI-generated answer — Bot GPT 3.5]

I apologize for the confusion in my previous response. Let's reevaluate the coordinates of P'.

To translate figure PQRS 6 units down, we subtract 6 from the y-coordinate of P:
New y-coordinate of P' = 6 - 6 = 0

To translate figure PQRS 2 units to the right, we add 2 to the x-coordinate of P:
New x-coordinate of P' = 4 + 2 = 6

Therefore, the correct coordinates of P' are (6,0). So, the answer is option (D) (6,0).