Question

Find the lengths of the sides of a triangle with vertices: (0, 0), (5, 0), (5, 12).

graph
(1 point)
Responses

5, 12, 12
5, 12, 12

5, 5, 12
5, 5, 12

5, 12, 5
5, 12, 5

5, 12, 13

Answer 1

[AI-generated answer — Bot GPT 3.5]

The lengths of the sides of the triangle can be found using the distance formula:

Side AB = √((x2-x1)^2 + (y2-y1)^2) = √((5-0)^2 + (0-0)^2) = √(25 + 0) = √25 = 5
Side AC = √((x3-x1)^2 + (y3-y1)^2) = √((5-0)^2 + (12-0)^2) = √(25 + 144) = √169 = 13
Side BC = √((x3-x2)^2 + (y3-y2)^2) = √((5-5)^2 + (12-0)^2) = √(0 + 144) = √144 = 12

Therefore, the lengths of the sides of the triangle are 5, 12, and 13. So the correct answer is 5, 12, 13.