To solve this system of equations, we can use the method of elimination by multiplying one or both equations to get equal coefficients for either x or y.
Here, we can eliminate x by multiplying the first equation by 1 and the second equation by 4:
(1) 4x + 3y = 6
(2) -4x + 2y = 14
After multiplying, the equations become:
(3) 4x + 3y = 6
(4) -16x + 8y = 56
Now, we can add equation (3) and equation (4):
(3) 4x + 3y = 6
(4) -16x + 8y = 56
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11y = 62
If we divide both sides of equation (5) by 11:
11y/11 = 62/11
y = 62/11
y = 6
Now we substitute the value of y back into any of the original equations. Let's use equation (1):
4x + 3(6) = 6
4x + 18 = 6
4x = 6 - 18
4x = -12
x = -12/4
x = -3
So the solution to the system of equations is:
x = -3
y = 6
Therefore, the correct answer is:
x = -3, y = 6