Apologies for the confusion. Let's solve the system of equations again:
Equation 1: x + 3y = 5
Equation 2: -x + 6y = 4
We can solve this system by either the substitution method or the elimination method. Here, we will use the elimination method to solve the system:
Multiply Equation 1 by -1 to make the x terms add up to zero:
-1(x + 3y) = -1(5)
-x - 3y = -5
Now, add the two equations together:
(-x + 6y) + (-x - 3y) = 4 + (-5)
-2x + 3y = -1
Now, we have a new equation:
-2x + 3y = -1 (Equation 3)
Now, let's solve Equation 3 along with Equation 2 to find the values of x and y:
(-2x + 3y) - (-x + 6y) = -1 - 4
-2x + 3y + x - 6y = -5
-x - 3y = -5 (Equation 4)
Equation 3: -2x + 3y = -1
Equation 4: -x - 3y = -5
Add the two equations together:
(-2x + x) + (3y - 3y) = (-1) + (-5)
-x = -6
Divide both sides by -1:
x = 6
Now substitute the value of x into Equation 1 to find the value of y:
6 + 3y = 5
3y = 5 - 6
3y = -1
y = -1/3
Therefore, the solution to the system of equations is x = 6 and y = -1/3.
The correct answer is x = 6 and y = -1/3.