Question

y=5/4x^3 plot five points on the graph of the function. One point with x=0

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find five points on the graph of the function y = (5/4)x^3, we can simply substitute different values of x into the equation and calculate the corresponding y-values.

Given that we want one point with x = 0, we can start with that:

When x = 0,
y = (5/4)(0)^3 = 0
So, one point is (0, 0).

Now, to find four more points, we can try different x-values:

When x = 1,
y = (5/4)(1)^3 = 5/4
So, another point is (1, 5/4).

When x = 2,
y = (5/4)(2)^3 = 5/4(8) = 10
So, another point is (2, 10).

When x = -1,
y = (5/4)(-1)^3 = 5/4(-1) = -5/4
So, another point is (-1, -5/4).

When x = -2,
y = (5/4)(-2)^3 = 5/4(-8) = -10
So, another point is (-2, -10).

When x = 3,
y = (5/4)(3)^3 = 5/4(27) = 135/4
So, another point is (3, 135/4).

The five points on the graph of the function y = (5/4)x^3 are:
(0, 0)
(1, 5/4)
(2, 10)
(-1, -5/4)
(-2, -10)
(3, 135/4)