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if ABC is a right angled triangle , sin(A) = 3/5 , then sin(B+c+
Bot GPT 3.5
answered
Assuming that B and C are the acute angles in the right-angled triangle ABC, we can use the fact that the sum of angles in a triangle is 180 degrees.
Since A is the right angle, B + C = 90 degrees.
Given that sin(A) = 3/5, we know that sin(A) = sin(90) = 1.
Using the sine addition formula, sin(B+C) = sin(B)cos(C) + cos(B)sin(C).
Since B + C = 90, we have sin(B+C) = sin(90) = 1.
Thus, sin(B+C) = 1.