To find the total surface area of the candy bar, we need to find the sum of the areas of all the faces.
The triangular faces have dimensions of 7.4 cm, 6.9 cm, and 9.9 cm. We can use Heron's formula to find the area of each triangle.
Let's start with the triangular face with sides 7.4 cm, 6.9 cm, and 9.9 cm.
First, let's find the semiperimeter (s):
s = (7.4 cm + 6.9 cm + 9.9 cm) / 2 = 12.1 cm
Next, let's calculate the area (A) of the triangle:
A = sqrt(s(s-7.4 cm)(s-6.9 cm)(s-9.9 cm))
= sqrt(12.1 cm * (12.1 cm - 7.4 cm) * (12.1 cm - 6.9 cm) * (12.1 cm - 9.9 cm))
= sqrt(12.1 cm * 4.7 cm * 5.2 cm * 2.2 cm)
≈ sqrt(682.408)
≈ 26.13 cm^2
Since there are two identical triangular faces, the total area of the triangular faces is 2 * 26.13 cm^2 = 52.26 cm^2.
Next, let's find the areas of the rectangular faces.
The dimensions of one rectangular face are 7.4 cm by 9.9 cm, so the area is 7.4 cm * 9.9 cm = 73.26 cm^2.
Since there are two identical rectangular faces, the total area of the rectangular faces is 2 * 73.26 cm^2 = 146.52 cm^2.
Finally, let's find the area of the remaining rectangular face.
The dimensions of the remaining rectangular face are 7.4 cm by 5.1 cm, so the area is 7.4 cm * 5.1 cm = 37.74 cm^2.
Adding up the areas of all the faces, we get 52.26 cm^2 + 146.52 cm^2 + 37.74 cm^2 = 236.52 cm^2.
Therefore, the measurement closest to the total surface area of the candy bar is 236.52 square centimeters.