The volume of a cone is given by the formula V = (1/3)Ï€r^2h, where r is the radius of the base of the cone and h is the height.
Since the diameter of the ice cream cone is equal to its height, we can let the diameter be d and the radius be r = d/2.
The volume of the ice cream cone is V_cone = (1/3)Ï€r^2h = (1/3)Ï€(d/2)^2(d) = (1/12)Ï€d^3.
The volume of the perfect hemisphere of ice cream on top of the cone is given as 4 in.3.
The formula for the volume of a perfect sphere is V_sphere = (4/3)Ï€r^3, where r is the radius of the sphere.
Since the diameter of the hemisphere is equal to the diameter of the cone, the radius of the hemisphere is r = d/2.
We are given that V_sphere = 4 in.3, so we can solve for d by setting V_sphere = (4/3)Ï€r^3 = (4/3)Ï€(d/2)^3 = (4/3)Ï€(d^3/8) = 4 in.3.
Simplifying, we have (4/3)Ï€(d^3/8) = 4 in.3.
Multiplying both sides by 3/4, we have π(d^3/8) = 3 in.3.
Multiplying both sides by 8/d^3, we have π = (3(8/d^3)) in.3/d^3.
Simplifying, we have π = 24/d^3 in.3/d^3.
Therefore, d^3 = 24/Ï€.
Taking the cube root of both sides, we have d = (24/Ï€)^(1/3).
Now that we have the diameter of the cone, we can find the volume of the cone by plugging it into the formula V_cone = (1/12)Ï€d^3.
V_cone = (1/12)Ï€((24/Ï€)^(1/3))^3 = (1/12)Ï€(24/Ï€) = 2 in.3.
Therefore, the total volume of ice cream in and on top of the cone is 4 in.3 (hemisphere) + 2 in.3 (cone) = 6 in.3.