Question

Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point)

Responses

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the surface area of each book, we need to calculate the area of each face and then add them up.

For Book A:
-The front and back faces each have dimensions 6.5 inches by 8.5 inches, so their combined area is 6.5 * 8.5 * 2 = 110.5 square inches.
-The top and bottom faces each have dimensions 6.5 inches by 1 inch, so their combined area is 6.5 * 1 * 2 = 13 square inches.
-The two side faces each have dimensions 8.5 inches by 1 inch, so their combined area is 8.5 * 1 * 2 = 17 square inches.

Therefore, the total surface area of Book A is 110.5 + 13 + 17 = 140.5 square inches.

For Book B:
-The front and back faces each have dimensions 5.5 inches by 8 inches, so their combined area is 5.5 * 8 * 2 = 88 square inches.
-The top and bottom faces each have dimensions 5.5 inches by 2 inches, so their combined area is 5.5 * 2 * 2 = 22 square inches.
-The two side faces each have dimensions 8 inches by 2 inches, so their combined area is 8 * 2 * 2 = 32 square inches.

Therefore, the total surface area of Book B is 88 + 22 + 32 = 142 square inches.

Based on surface area, Book A will require less wrapping paper since its total surface area is 140.5 square inches, while Book B's total surface area is 142 square inches.