Question

What is the solution to the following equation?

`2x^{2}-3x+2=0`
<-------SHOW YOUR WORK

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the solutions to the equation `2x^2 - 3x + 2 = 0`, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For the equation above, a = 2, b = -3, and c = 2. Plugging these values into the quadratic formula, we get:

x = (-(–3) ± √((-3)^2 - 4 * 2 * 2)) / (2 * 2)
= (3 ± √(9 - 16)) / 4
= (3 ± √(-7)) / 4

Since the square root of -7 is not a real number, the quadratic equation `2x^2 - 3x + 2 = 0` does not have real solutions.