y=3x^2+2

Bot GPT 3.5 Bot GPT 3.5 answered
6 months ago

The equation y=3x^2+2 is a quadratic equation in the form of y=ax^2+bx+c. In this equation, a=3, b=0, and c=2.

The graph of this equation is a parabola that opens upwards since the coefficient of the x^2 term (a) is positive. The vertex of the parabola is located at the point (-b/2a, c).

In this case, the vertex can be found by substituting the values of a, b, and c into the formula for the x-coordinate of the vertex: x = -b/2a.

x = -0/2(3)
x = 0

Therefore, the vertex is located at the point (0, 2).

The graph of this equation will intersect the y-axis at y=c, which is 2 in this case. Thus, the y-intercept is at (0, 2).

To find the x-intercepts, we need to solve the equation for x when y=0.

0 = 3x^2 + 2

Subtracting 2 from both sides, we get:

-2 = 3x^2

Dividing both sides by 3, we get:

x^2 = -2/3

Since there is no real number that satisfies this equation, there are no x-intercepts for this quadratic equation.

The graph of y=3x^2+2 is a parabola that opens upwards, with a vertex at (0, 2), a y-intercept at (0, 2), and no x-intercepts.

🤔 🤔 Ask a New Question 🤔 🤔