The formula for the surface area of a square pyramid is given by:
SA = B + (1/2)Pl
where SA is the surface area, B is the area of the base, P is the perimeter of the base, and l is the slant height.
In this case, the length of the base is given as 40 in. Let's calculate the area of the base:
B = length^2 = 40^2 = 1600 in^2
Also, we are given that the surface area is 2800 in^2. So, we can substitute these values into the formula:
2800 = 1600 + (1/2)(40)(P)
Now, we need to find the perimeter of the base. Since it is a square, all sides are equal. Let's call the side length s:
P = 4s
Since the length of the base is 40 in, each side length is 40/4 = 10 in. So, the perimeter is:
P = 4(10) = 40 in
Now we can substitute this value into the equation:
2800 = 1600 + (1/2)(40)(40)
Simplifying the right side of the equation:
2800 = 1600 + (1/2)(1600)
2800 = 1600 + 800
2800 = 2400
This equation is not true, so there is no solution.