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Since the exterior angle is equal to the sum of the two remote interior angles, we have $180^\circ = x + 125^\circ$, which implies $x=\boxed{55^\circ}$. [asy]
pair A,B,C;
A=(0,0);
B=(80,0);
C=(30,50);
draw(A--B--C--cycle);
label("x",C,N);
label("80",B,SE);
label("75",C,NW);
draw(C--(70,0),dashed);
[/asy]