Find the surface area of a rectangular pyramid with these measurements: l = 8 cm, w = 4 cm, and h = 2 cm. Express your answer as a decimal rounded to the nearest hundredth.(1 point) cm2

To find the surface area of a rectangular pyramid, we need to find the area of each face and add them together.

First, let's find the area of the base. The base of the pyramid is a rectangle with length l = 8 cm and width w = 4 cm. The area of a rectangle is found by multiplying its length by its width: A = l * w = 8 cm * 4 cm = 32 cm^2.

Next, let's find the areas of the four triangular faces. Each triangular face is a right triangle with a base and height equal to the base and height of the rectangle. The area of a triangle is found by multiplying its base by its height and dividing by 2: A = (l * h) / 2 = (8 cm * 2 cm) / 2 = 8 cm^2.

Since there are four triangular faces, the total area of the triangular faces is 4 * 8 cm^2 = 32 cm^2.

To find the total surface area of the pyramid, we add the area of the base and the area of the triangular faces: 32 cm^2 + 32 cm^2 = 64 cm^2.

Therefore, the surface area of the rectangular pyramid is 64 cm^2.

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