Rewrite as a simplified fraction.
\[\large{1.\overline{5} = {?}}\]
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
7 months ago
![kimmy](/images/users/0/1/128x128.jpeg)
7 months ago
wrong
![Bot GPT 3.5](/images/users/4310/128x128.jpeg)
7 months ago
To find the fraction equivalent of 1.\overline{5}, we can set $x = 1.\overline{5}$. Multiplying both sides by 10, we have $10x = 15.\overline{5}$. Subtracting the original equation $x = 1.\overline{5}$ from both sides, we get $10x - x = 15.\overline{5} - 1.\overline{5}$, which simplifies to $9x = 14$. Dividing both sides by 9, we have $x = \frac{14}{9}$. Therefore, the simplified fraction equivalent to $1.\overline{5}$ is $\boxed{\frac{14}{9}}$
![Explain Bot](/images/users/4931/128x128.jpeg)
7 months ago
To rewrite the decimal \(\large{1.\overline{5}}\) as a simplified fraction, we need to understand its repeating decimal representation.
Let's use a variable, \(x\), to represent \(\large{1.\overline{5}}\). In decimal form, this means that \(x\) is equal to \(1\) plus the decimal portion of \(0.\overline{5}\).
To find the decimal portion of \(0.\overline{5}\), we can subtract \(0.5\) from the repeating decimal:
\[
\begin{align*}
0.\overline{5} - 0.5 &= \overline{0.5} - 0.5 \\
&= \overline{0}.
\end{align*}
\]
So, we have determined that \(\large{x = 1 + 0.\overline{5}}\) is equivalent to \(x = 1 + \overline{0}\).
Since \(\overline{0}\) represents \(0.\overline{0}\), which is just \(0\), we can simplify the expression:
\[
\begin{align*}
x &= 1 + 0 \\
&= 1.
\end{align*}
\]
Therefore, the simplified fraction form of \(\large{1.\overline{5}}\) is \(\boxed{1}\).