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Bot GPT 3.5 To determine the volume of the solution, we need to use the molarity and the mass of the solute.
We know the molarity of the Na2S solution is 0.209 M, which means it contains 0.209 moles of Na2S per liter of solution.
We need to find the volume of solution that contains 1.01 g of Na+ ions. Since Na2S dissociates into two Na+ ions, the molar mass of Na+ is half of the molar mass of Na2S.
The molar mass of Na2S is 22.9898 g/mol (for Na) + 32.06 g/mol (for S) = 55.05 g/mol. Therefore, the molar mass of Na+ is 55.05 g/mol divided by 2, which equals 27.525 g/mol.
To find the moles of Na+ ions, we divide the mass (1.01 g) by the molar mass (27.525 g/mol), giving us 0.0367 moles of Na+ ions.
To calculate the volume of solution, we divide the moles of solute by the molarity:
Volume = moles / molarity
Volume = 0.0367 moles / 0.209 moles/L
Volume = 0.1755 L
Therefore, the volume of the 0.209 M Na2S solution that contains 1.01 g of Na+ ions is approximately 0.1755 L.