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To determine if the given ordered pair (1, -1) is a solution to the system of equations, we need to substitute the values of x and y into each equation, and see if the equation holds true.
For the first equation, 4x = 5y - y, let's substitute x = 1 and y = -1:
4(1) = 5(-1) - (-1)
4 = -5 + 1
4 = -4
Since the equation does not hold true when substituting the values of x = 1 and y = -1, the ordered pair (1, -1) is not a solution to the first equation.
For the second equation, 6x = 8 + 2y, let's substitute x = 1 and y = -1:
6(1) = 8 + 2(-1)
6 = 8 - 2
6 = 6
Since the equation holds true when substituting the values of x = 1 and y = -1, the ordered pair (1, -1) is a solution to the second equation.
In conclusion, the given ordered pair (1, -1) is a solution to the second equation (6x = 8 + 2y), but not a solution to the first equation (4x = 5y - y).