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To find the equation of a line, you can use the point-slope form of a linear equation, which is given by:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line, and m is the slope of the line.
In this case, the point (2, 6) lies on the line, and the slope is -1/2. Plugging these values into the equation, we get:
y - 6 = (-1/2)(x - 2)
Next, we can simplify the equation:
y - 6 = (-1/2)x + 1
To put the equation into slope-intercept form (y = mx + b), we can move -6 to the other side and simplify:
y = (-1/2)x + 7
Therefore, the equation of the line that passes through the point (2,6) with a slope of -1/2 is y = (-1/2)x + 7.