To determine which function was used to create the input-output table, we can evaluate each given function at one or more of the x-values from the table and check whether the function yields the corresponding f(x) from the table.
Let's evaluate each function for x = -2 (since this is a unique value that should help us eliminate incorrect functions):
1. f(x) = 3x^2 + 1
f(-2) = 3(-2)^2 + 1
f(-2) = 3(4) + 1
f(-2) = 12 + 1
f(-2) = 13
This does not match the table (f(-2) = -11).
2. f(x) = 3x + 1
f(-2) = 3(-2) + 1
f(-2) = -6 + 1
f(-2) = -5
This does not match the table (f(-2) = -11).
3. f(x) = −3x^2 + 1
f(-2) = −3(-2)^2 + 1
f(-2) = −3(4) + 1
f(-2) = −12 + 1
f(-2) = -11
This matches the table (f(-2) = -11).
4. f(x) = 6x + 1
f(-2) = 6(-2) + 1
f(-2) = -12 + 1
f(-2) = -11
Although this matches the value at x = -2, we need to check other values to ensure this is not a coincidence.
To confirm our selection, let's evaluate the third function (f(x) = −3x^2 + 1) at x = -1 and x = 0 (both provided in the table):
For x = -1:
f(x) = −3x^2 + 1
f(-1) = −3(-1)^2 + 1
f(-1) = −3(1) + 1
f(-1) = −3 + 1
f(-1) = -2
This matches the table (f(-1) = -2).
For x = 0:
f(x) = −3x^2 + 1
f(0) = −3(0)^2 + 1
f(0) = −3(0) + 1
f(0) = 0 + 1
f(0) = 1
This matches the table (f(0) = 1).
Given that f(x) = −3x^2 + 1 matches all provided values in the table, we can conclude that the correct function is:
f(x) = −3x^2 + 1