To calculate the volume of a cone, you can use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where \(V\) is the volume, \(r\) is the radius of the base of the cone, and \(h\) is the height of the cone.
You stated the radius \(r\) is 5 inches and the height \(h\) is 9 inches.
Plugging these values into the formula, we get:
\[ V = \frac{1}{3} \pi (5\text{ in})^2 (9\text{ in}) \]
\[ V = \frac{1}{3} \pi (25\text{ in}^2) (9\text{ in}) \]
\[ V = \frac{1}{3} \pi (225\text{ in}^3) \]
\[ V = 75\pi\text{ in}^3 \]
To get a numerical value, we can approximate \(\pi\) as 3.14159:
\[ V \approx 75 \times 3.14159\text{ in}^3 \]
\[ V \approx 235.5\text{ in}^3 \]
Thus, the volume of the cone is approximately 235.5 cubic inches.