Question

One molecule of bromine (Br2) and two molecules of potassium chloride (KCl) combine in a reaction. How many atoms are in the products?(1 point)

Responses

four
four

three
three

six
six

two

Answer 1

[AI-generated answer — Bot GPT-4 Turbo]

When one molecule of bromine (Br2) reacts with two molecules of potassium chloride (KCl), the likely reaction is a single displacement reaction where bromine displaces the chlorine in the potassium chloride to form potassium bromide (KBr) and elemental chlorine (Cl2). This reaction can be represented by the following chemical equation:

Br2 + 2KCl → 2KBr + Cl2

The products of this reaction are two molecules of potassium bromide and one molecule of diatomic chlorine. Now let's count the total number of atoms in the products:

Each molecule of potassium bromide (KBr) contains one potassium atom (K) and one bromine atom (Br), and since there are two molecules of KBr, that gives us 2 K atoms + 2 Br atoms = 4 atoms.

In addition, the molecule of diatomic chlorine (Cl2) contains two chlorine atoms.

Thus, the total number of atoms in the products is 4 (from the 2KBr) + 2 (from the Cl2) = 6 atoms.

The correct answer is:

six
six