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To find the number of feet the diver is above the ocean after 2 seconds, we plug \( t = 2 \) into the formula given:
\[ h = 75 - 16t^2 \]
Plugging \( t = 2 \) into the formula:
\[ h = 75 - 16(2)^2 \]
\[ h = 75 - 16(4) \]
\[ h = 75 - 64 \]
\[ h = 11 \]
So, the competitive cliff-diver is 11 feet above the ocean after 2 seconds.