Question

What is the irrational square root √63 rewritten as the product of an integer and another irrational square root, in simplest form?(1 point)

Answer 1

[AI-generated answer — Bot GPT-4 Turbo]

To simplify √63 as the product of an integer and another irrational square root in its simplest form, you would factor 63 into its prime factors and then separate those factors into pairs of equal factors:

63 = 3 × 3 × 7

Now, look for pairs of the same number. There is a pair of 3's, which can be taken out of the square root because √(3×3) = 3. The 7, however, does not have a pair and must remain under the square root:

√63 = √(3×3×7) = √(3²×7) = 3√7

The final expression 3√7 is the simplified form of √63 as the product of an integer (3) and another irrational square root (√7).