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To find the zeros of the quadratic equation y = x^2 + 2x - 8, we set y equal to 0 and solve for x. The equation becomes:
0 = x^2 + 2x - 8
Now, we can factor or use the quadratic formula to solve for x:
Using factoring:
0 = (x - 2)(x + 4)
Setting each factor equal to zero:
x - 2 = 0 or x + 4 = 0
Solving for x:
x = 2 or x = -4
Therefore, the zeros of the quadratic equation y = x^2 + 2x - 8 are x = 2 and x = -4.