Question

Find the focus of the parabola equation y2+36=0 is

Answer 1

[AI-generated answer — Bot GPT 3.5]

The given equation is y^2 + 36 = 0.

We can rewrite this equation in the standard form of a parabola as (y - k)^2 = 4a(x - h), where (h, k) is the vertex and "a" is a constant determining the shape and orientation of the parabola.

Comparing the given equation to the standard form, we have:
(y - 0)^2 = 4(1)(x - 0)
y^2 = 4x

From this, we can see that the focus of the parabola is the point (a, 0), where "a" is equal to 1/4 times the coefficient of x in the standard form equation.
In this case, a = 1/4(4) = 1.

Therefore, the focus of the parabola y^2 + 36 = 0 is (1, 0).