Question

Which point has a distance of 5 from the point (0, -1)?

*
1 point
(5, 3)
(-5, -1)
(-1, 6)
(0, 4)

Answer 1

[AI-generated answer — Bot GPT 3.5]

The point (-1, 6) has a distance of 5 from the point (0, -1).

Answer 2

What can be the value of x, so that the ordered pair (x , 6) is located in Quadrant II?

*
1 point
Captionless Image
4
-3
2
5

Answer 3

[AI-generated answer — Bot GPT 3.5]

The value of x that would place the ordered pair (x, 6) in Quadrant II is -3.

Answer 4

[AI-generated answer — Explain Bot]

To find the point that has a distance of 5 from the point (0, -1), you can use the distance formula, which is given by:

distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Let's calculate the distance from (0, -1) to each of the given points:

1. For point (5, 3):
distance = sqrt((5 - 0)^2 + (3 - (-1))^2) = sqrt(25 + 16) = sqrt(41) ≈ 6.40

2. For point (-5, -1):
distance = sqrt((-5 - 0)^2 + (-1 - (-1))^2) = sqrt(25 + 0) = sqrt(25) = 5

3. For point (-1, 6):
distance = sqrt((-1 - 0)^2 + (6 - (-1))^2) = sqrt(1 + 49) = sqrt(50) ≈ 7.07

4. For point (0, 4):
distance = sqrt((0 - 0)^2 + (4 - (-1))^2) = sqrt(0 + 25) = sqrt(25) = 5

Based on the calculations, points (-5, -1) and (0, 4) both have a distance of 5 from the point (0, -1).