To simplify the expression 2√8 + 3√8, we can combine like terms.
Both terms have the same radical, which is √8.
Therefore, we can simplify the expression as follows:
2√8 + 3√8 = (2 + 3)√8 = 5√8
So, 2√8 + 3√8 simplifies to 5√8.
Both terms have the same radical, which is √8.
Therefore, we can simplify the expression as follows:
2√8 + 3√8 = (2 + 3)√8 = 5√8
So, 2√8 + 3√8 simplifies to 5√8.
Since both terms have the same radical (√31), we can simplify the expression as follows:
√31 + √31 = (1 + 1)√31 = 2√31
So, √31 + √31 simplifies to 2√31.
To add √31 + √31, we can combine the two radical terms since they have the same root (√31).
√31 + √31 = 2√31
So, √31 + √31 simplifies to 2√31.
To add √31 + √31, we can't directly combine the two radicals since they are not like terms.
So, the sum of √31 + √31 cannot be further simplified. The final result is 2√31.
Both terms have the same radical, which is √5.
Therefore, we can subtract the coefficients and keep the radical the same:
7√5 - 4√5 = (7 - 4)√5 = 3√5
So, 7√5 - 4√5 simplifies to 3√5.
Both terms have the same radical, which is √29.
Therefore, we can subtract the coefficients and keep the radical the same:
√29 - √29 = (1 - 1)√29 = 0√29 = 0
So, √29 - √29 simplifies to 0.
The difference is ____ centimeters
8√2 - 9√2 = -√2
So, the difference in the length of the diagonals is -√2 centimeters.
Both terms have the same radical, which is √21.
Therefore, we can add the coefficients and keep the radical the same:
3√21 + 7√21 = (3 + 7)√21 = 10√21
So, 3√21 + 7√21 simplifies to 10√21.
Both terms have the same radical, which is √19.
Therefore, we can add the coefficients and keep the radical the same:
√19 + √19 = (1 + 1)√19 = 2√19
So, √19 + √19 simplifies to 2√19.
Since all three terms have the same radical, which is √, we can add the coefficients:
22√3 + 32√ + 2√ = (22 + 32 + 2)√ = 56√
So, 22√3 + 32√ + 2√ simplifies to 56√.
All three terms have the same radical, which is √22.
Therefore, we can add the coefficients:
^3√22 + 3√22 + √22 = (^3 + 3 + 1)√22 = 7√22
So, ^3√22 + 3√22 + √22 simplifies to 7√22.
All three terms have the same radical, which is √22.
Therefore, we can add the coefficients:
3√22 + 3√22 + √22 = (3 + 3 + 1)√22 = 7√22
So, 3√22 + 3√22 + √22 simplifies to 7√22.
Both terms have the same radical, which is √23.
Therefore, we can subtract the coefficients and keep the radical the same:
8√23 - √23 = (8 - 1)√23 = 7√23
So, 8√23 - √23 simplifies to 7√23.
7√6 - 5√6 = (√6)(7 - 5) = 2√6
So, the difference in miles run each day is 2√6 miles.
To add 3√22 + 4√22, since both terms have the same radical, we can combine them by adding the coefficients:
3√22 + 4√22 = (3 + 4)√22 = 7√22
So, the correct answer for question 3 is 7√22.