1. Solve the system of two linear equations. −3x − 4y = −23

3x − 5y = 5
2. How many solutions does the system of equations have?
8x−6y=48
8x+6y=48

Bot GPT 3.5 Bot GPT 3.5 answered
7 months ago

1. To solve the system of equations −3x − 4y = −23 and 3x − 5y = 5, we can use the method of elimination.

First, we multiply the second equation by -1 to make the coefficients of x the same magnitude but with opposite signs:
-1(3x - 5y) = -1(5)
-3x + 5y = -5

Now we can add the two equations together:
(-3x - 4y) + (-3x + 5y) = (-23) + (-5)
-6x + y = -28

To eliminate the y variable, we can multiply the first equation by 5 and the second equation by 4:
5(-3x - 4y) = 5(-23)
-15x - 20y = -115

4(-6x + y) = 4(-28)
-24x + 4y = -112

Adding the two equations together:
(-15x - 20y) + (-24x + 4y) = (-115) + (-112)
-39x - 16y = -227

Now we have a new equation:
-39x - 16y = -227

To solve for x, we can divide the equation by -39:
-39x/-39 - 16y/-39 = -227/-39
x + (16/39)y = 227/39

So the solution for x in terms of y is:
x = (227/39) - (16/39)y

To find y, we can substitute this expression for x into any of the original equations. Let's use the first equation:

-3x - 4y = -23
-3[(227/39) - (16/39)y] - 4y = -23

Simplifying:
(-3)(227/39) + (3)(16/39)y - 4y = -23
(-681/39) + (48/39)y - 4y = -23
(-681 + 48y - 156y)/39 = -23
(-681 - 108y)/39 = -23
-681 - 108y = (-23)(39)
-681 - 108y = -897

Now we can solve for y:
-108y = -897 + 681
-108y = -216
y = (-216)/(-108)
y = 2

Now we can substitute y = 2 into the expression for x:
x = (227/39) - (16/39)(2)
x = (227/39) - (32/39)
x = (227 - 32)/39
x = 195/39
x = 5

So the solution to the system of equations −3x − 4y = −23 and 3x − 5y = 5 is x = 5 and y = 2.

2. The system of equations 8x − 6y = 48 and 8x + 6y = 48 has infinitely many solutions. This is because the two equations represent parallel lines with the same slope and different y-intercepts. The two lines will never intersect, so any value of x and y that satisfies one equation will also satisfy the other.

cherry cherry answered
7 months ago

Solve the system of two equations using elimination with multiplication.

4x−6y=−48
−2x+4y=30

Bot GPT 3.5 Bot GPT 3.5 answered
7 months ago

To solve the system of equations 4x - 6y = -48 and -2x + 4y = 30, we will use the method of elimination with multiplication.

First, let's multiply the first equation by 2 and the second equation by 3 to make the coefficients of x match with opposite signs:
2(4x - 6y) = 2(-48)
3(-2x + 4y) = 3(30)

This gives us:
8x - 12y = -96
-6x + 12y = 90

Now, we can add the two equations together to eliminate the y variable:
(8x - 12y) + (-6x + 12y) = (-96) + 90
2x = -6

Dividing both sides of the equation by 2, we get:
x = -3

Now we can substitute x = -3 into one of the original equations, let's use the first equation:
4(-3) - 6y = -48
-12 - 6y = -48

Adding 12 to both sides of the equation:
-6y = -36

Dividing both sides of the equation by -6, we get:
y = 6

Therefore, the solution to the system of equations 4x - 6y = -48 and -2x + 4y = 30 is x = -3 and y = 6.

cherry cherry answered
7 months ago

Solve the system of equations.

3x−4y=40
5x−5y=55

Bot GPT 3.5 Bot GPT 3.5 answered
7 months ago

To solve the system of equations 3x - 4y = 40 and 5x - 5y = 55, we can use the method of substitution.

First, let's solve one of the equations for one variable in terms of the other variable. We'll solve the first equation for x:
3x - 4y = 40
3x = 4y + 40
x = (4y + 40)/3

Now we can substitute this expression for x into the second equation:
5((4y + 40)/3) - 5y = 55

Simplifying:
(20y + 200)/3 - 5y = 55

Multiplying both sides of the equation by 3 to eliminate the fraction:
20y + 200 - 15y = 165

Combining like terms:
5y + 200 = 165

Subtracting 200 from both sides of the equation:
5y = -35

Dividing both sides of the equation by 5:
y = -7

Now we can substitute this value of y into the expression for x:
x = (4(-7) + 40)/3
x = (28 + 40)/3
x = 68/3

So the solution to the system of equations 3x - 4y = 40 and 5x - 5y = 55 is x = 68/3 and y = -7.

cherry cherry answered
7 months ago

Solve the system of equations.

3x − 4y = 40
5x − 5y = 55

Bot GPT 3.5 Bot GPT 3.5 answered
7 months ago

To solve the system of equations 3x − 4y = 40 and 5x − 5y = 55, we can use the method of elimination.

First, let's multiply the first equation by 5 and the second equation by 3 to make the coefficients of x match:
5(3x − 4y) = 5(40)
3(5x − 5y) = 3(55)

This gives us:
15x - 20y = 200
15x - 15y = 165

Now, we can subtract the second equation from the first equation to eliminate the x variable:
(15x - 20y) - (15x - 15y) = 200 - 165
-20y + 15y = 35
-5y = 35

Dividing both sides of the equation by -5, we get:
y = -7

Now we can substitute this value of y into one of the original equations, let's use the first equation:
3x - 4(-7) = 40
3x + 28 = 40

Subtracting 28 from both sides of the equation:
3x = 12

Dividing both sides of the equation by 3, we get:
x = 4

Therefore, the solution to the system of equations 3x − 4y = 40 and 5x − 5y = 55 is x = 4 and y = -7.

cherry cherry answered
7 months ago

How many solutions does the system have?

12x − 15y = 18
4x − 5y = 6

Bot GPT 3.5 Bot GPT 3.5 answered
7 months ago

To determine how many solutions the system of equations 12x - 15y = 18 and 4x - 5y = 6 has, we can compare the slopes of the two equations.

First, let's rewrite the equations in slope-intercept form (y = mx + b):
12x - 15y = 18 => -15y = -12x + 18 => y = (4/5)x - (6/5)
4x - 5y = 6 => -5y = -4x + 6 => y = (4/5)x - (6/5)

As we can see, the two equations have the same slope of 4/5. When two lines have the same slope, they are parallel to each other.

Since the lines are parallel and have the same slope, they will never intersect. Therefore, the system has no solution.

In conclusion, the system of equations 12x - 15y = 18 and 4x - 5y = 6 has no solution.

cherry cherry answered
7 months ago

An artist uses 60 pounds of clay to make 80 bowls. The ratio of pounds of clay she uses to the number of bowls she makes is a proportional relationship.

Select all the true statements.

(1 point)
Responses

The graph of the proportional relationship has a slope of 3/4.

The proportional relationship has a unit rate of 4/3 a pound of clay per bowl.

She will use 20 pounds of clay to make 15 bowls.

She will use 75 pounds of clay to make 100 bowls.

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