To find the value of b, we can use the fact that the sum of the solutions of a quadratic equation in the form of ax^2 + bx + c = 0 is equal to -b/a, and the product of the solutions is equal to c/a.
Given that the solutions are -11 and 5, the sum of the solutions is -11 + 5 = -6. This means that -b/a = -6.
Also, the product of the solutions is -11 * 5 = -55. This means that c/a = -55.
We can solve these two equations simultaneously to find the value of b.
-b/a = -6
c/a = -55
Rearranging the first equation, we have:
b/a = 6
Multiplying both sides of the second equation by a, we get:
c = -55a
Since c = -55, we have:
-55 = -55a
a = 1
Substituting this value of a into b/a = 6, we can find b:
b/1 = 6
b = 6
Therefore, the value of b in the quadratic equation x^2 + bx - 55 = 0, whose solutions are -11 and 5, is 6.