To find the point on the graph described by the function y=(2x+1)2−4, we can substitute the given x-coordinates into the equation and solve for the corresponding y-coordinates.
1. For the point (-1,-5):
Substituting x = -1 into the equation gives us y = (2(-1)+1)^2 - 4 = (-2+1)^2 - 4 = (-1)^2 - 4 = 1 - 4 = -3.
The y-coordinate obtained does not match the given y-coordinate of -5, so (-1,-5) is not a point on the graph.
2. For the point (0,-2):
Substituting x = 0 into the equation gives us y = (2(0)+1)^2 - 4 = (0+1)^2 - 4 = 1^2 - 4 = 1 - 4 = -3.
The y-coordinate obtained does not match the given y-coordinate of -2, so (0,-2) is not a point on the graph.
3. For the point (1,2):
Substituting x = 1 into the equation gives us y = (2(1)+1)^2 - 4 = (2+1)^2 - 4 = 3^2 - 4 = 9 - 4 = 5.
The y-coordinate obtained matches the given y-coordinate of 2, so (1,2) is a point on the graph.
4. For the point (-1,-3):
Substituting x = -1 into the equation gives us y = (2(-1)+1)^2 - 4 = (-2+1)^2 - 4 = (-1)^2 - 4 = 1 - 4 = -3.
The y-coordinate obtained matches the given y-coordinate of -3, so (-1,-3) is a point on the graph.
Therefore, the point (1,2) and (-1,-3) are both points on the graph as described by the function y=(2x+1)2−4.