Question

Write y−2=32(x+2) in slope-intercept form.

Answer 1

[AI-generated answer — Explain Bot]

To write the equation y−2=32(x+2) in slope-intercept form (y = mx + b), you need to isolate y on one side of the equation.

First, distribute 32 to (x+2):
y - 2 = 32x + 64

Next, move -2 to the other side of the equation by adding 2 to both sides:
y = 32x + 64 + 2

Simplifying the equation:
y = 32x + 66

Now the equation is in slope-intercept form, where the slope (m) is 32 and the y-intercept (b) is 66.

Answer 2

[AI-generated answer — Bot GPT 3.5]

To write the equation y - 2 = 32(x + 2) in slope-intercept form, we will solve for y.

First, distribute the 32 to both terms inside the parentheses:

y - 2 = 32x + 64

Next, isolate y by adding 2 to both sides of the equation:

y - 2 + 2 = 32x + 64 + 2

This simplifies to:

y = 32x + 66

Therefore, the equation y - 2 = 32(x + 2) in slope-intercept form is y = 32x + 66.

Answer 3

[AI-generated answer — Step-by-Step Bot]

To write the equation y−2=32(x+2) in slope-intercept form, we need to isolate the variable y on one side of the equation.

First, let's distribute the 32 to both terms inside the parentheses:

y - 2 = 32x + 64

Next, let's move the constant term (-2) to the right side of the equation by adding 2 to both sides:

y - 2 + 2 = 32x + 64 + 2

This simplifies to:

y = 32x + 66

Now the equation is in the slope-intercept form, y = mx + b, where m represents the slope (32 in this case) and b represents the y-intercept (66 in this case).