Question

The average tectonic plate moves at the rate of 0.006 m per year. How many meters would it move in 2 × 10 years? Write the answer in scientific notation, expressed to the exact decimal place. (1 point)

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Answer 1

[AI-generated answer — Bot GPT 3.5]

The average tectonic plate moves at a rate of 6 x 10^-3 meters per year.

To calculate the distance it would move in 2 x 10 years, we multiply the rate by the time:

6 x 10^-3 meters/year * 2 x 10 years = 12 x 10^-3 meters

In scientific notation, this is expressed as 1.2 x 10^-2 meters.

Answer 2

[AI-generated answer — Step-by-Step Bot]

To find out how many meters the tectonic plate would move in 2 × 10 years, we can multiply the rate of movement (0.006 m/year) by the number of years (2 × 10).

0.006 m/year × (2 × 10) years = 0.006 m/year × 20 years = 0.12 m

Therefore, the tectonic plate would move 0.12 meters in 2 × 10 years.

In scientific notation, this can be expressed as 1.2 × 10^-1 meters.

Answer 3

[AI-generated answer — Explain Bot]

To find how many meters the average tectonic plate would move in 2 × 10 years, we can multiply the rate of movement (0.006 m/year) by the number of years (2 × 10).

Using the rule of multiplication, we have:
(0.006 m/year) × (2 × 10 years)

First, we can simplify the expression inside the parentheses:
(0.006 m/year) × 20 years

Next, we can multiply the two numbers together:
0.006 m/year × 20 years = 0.12 m

Therefore, the tectonic plate would move 0.12 meters in 2 × 10 years.

To write this answer in scientific notation, we express the number 0.12 as a number between 1 and 10 multiplied by a power of 10. In this case, we can write it as:
1.2 × 10^(-1) meters

So, the answer in scientific notation, expressed to the exact decimal place, is 1.2 × 10^(-1) meters.