Question

add 5√10 + √10

A. √25
B. 6√20
C. √60
D. 6√10

Answer 1

[AI-generated answer — Bot GPT 3.5]

To add these two terms, we first recognize that they have a common factor of $\sqrt{10}$. We can factor that out to get $5\sqrt{10} + \sqrt{10} = (5+1)\sqrt{10} = \boxed{6\sqrt{10}}$.

Answer 2

[AI-generated answer — Explain Bot]

To add the expressions 5√10 and √10, we can combine the like terms. Both expressions have √10, so we can simply add the coefficients, which are 5 and 1.

5√10 + √10 = (5 + 1)√10 = 6√10

Therefore, the correct answer is D. 6√10.

Answer 3

[AI-generated answer — Step-by-Step Bot]

To add 5√10 and √10, we can combine the like terms. Since both terms have √10, we simply add the coefficients in front of √10.

5√10 + √10 = (5 + 1)√10 = 6√10

Therefore, the correct answer is option D. 6√10

Answer 4

subtract 11√19 - √19

Answer 5

[AI-generated answer — Bot GPT 3.5]

To subtract these two terms, we subtract the coefficients in front of $\sqrt{19}$.

$11\sqrt{19} - \sqrt{19} = (11 - 1)\sqrt{19} = 10\sqrt{19}$.

Therefore, the correct answer is $\boxed{10\sqrt{19}}$.

Answer 6

multiply (5√19) (6√2) give an exact answer

Answer 7

[AI-generated answer — Bot GPT 3.5]

To multiply these two terms, we multiply the coefficients and the radicands separately.

$(5\sqrt{19})(6\sqrt{2}) = 5 \cdot 6 \cdot \sqrt{19} \cdot \sqrt{2} = 30 \sqrt{38}$.

Therefore, the exact answer is $\boxed{30\sqrt{38}}$.

Answer 8

divide √95/3√5 provide an exact answer

Answer 9

[AI-generated answer — Bot GPT 3.5]

To divide these two terms, we rationalize the denominator by multiplying both the numerator and denominator by the conjugate of the denominator, which is $\sqrt{5}$.

$\frac{\sqrt{95}}{3\sqrt{5}} = \frac{\sqrt{95}}{3\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}}$

Simplifying the denominator, we have:

$\frac{\sqrt{95}\cdot \sqrt{5}}{3\sqrt{5} \cdot \sqrt{5}} = \frac{\sqrt{475}}{3\cdot 5}$

Finally, simplifying the square root of 475 and multiplying in the denominator, we obtain:

$\frac{\sqrt{475}}{3 \cdot 5} = \boxed{\frac{\sqrt{19}}{3}}$.

Answer 10

divide 36√39/9√13 provide an exact answer

Answer 11

[AI-generated answer — Bot GPT 3.5]

To divide these two terms, we can simplify the numerator and denominator separately, and then divide.

The numerator simplifies as follows:
$36\sqrt{39} = 6\cdot 6\sqrt{39} = 6\cdot 6\sqrt{3\cdot 13} = 6\cdot 6\sqrt{3}\cdot \sqrt{13} = 36\sqrt{3}\sqrt{13} = 36\sqrt{39}$.

The denominator simplifies as follows:
$9\sqrt{13} = 3\cdot 3\sqrt{13} = 3\cdot 3\sqrt{13}$.

Dividing the numerator by the denominator, we have:
$\frac{36\sqrt{39}}{9\sqrt{13}} = \frac{36}{9} \cdot \frac{\sqrt{39}}{\sqrt{13}} = 4\cdot \frac{\sqrt{39}}{\sqrt{13}} = 4\cdot \sqrt{\frac{39}{13}} = 4\cdot \sqrt{3}$.

Therefore, the exact answer is $\boxed{4\sqrt{3}}$.

Answer 12

simplify √48

Answer 13

[AI-generated answer — Bot GPT 3.5]

To simplify $\sqrt{48}$, we can factor the number under the square root sign:

$\sqrt{48} = \sqrt{16 \cdot 3} = \sqrt{16} \cdot \sqrt{3} = 4 \cdot \sqrt{3}$.

Therefore, the simplified form of $\sqrt{48}$ is $\boxed{4\sqrt{3}}$.

Answer 14

simplify 3^√54

note: you will find the option to add a cubic root symbol in the algebra (x) keyboard

Answer 15

[AI-generated answer — Bot GPT 3.5]

To simplify $3^{\sqrt{54}}$, we can start by simplifying the expression under the exponent.

$\sqrt{54}$ can be simplified as follows:
$\sqrt{54} = \sqrt{9 \cdot 6} = \sqrt{9} \cdot \sqrt{6} = 3 \cdot \sqrt{6}$.

Now we can rewrite the original expression as:
$3^{\sqrt{54}} = 3^{3 \cdot \sqrt{6}}$.

Since the exponent is in the form of $3 \cdot \sqrt{6}$, we can rewrite it as the cubic root of $(\sqrt{6})^3$:
$3^{\sqrt{54}} = 3^{\sqrt{6^3}}$.

Now we can see that $3$ raised to the cubic root power of $6^3$ will simply be $\boxed{6}$.

Answer 16

what is the irrational square root √63 rewritten as the product of an integer and another irrational square root in simplest form?

Answer 17

[AI-generated answer — Bot GPT 3.5]

To rewrite $\sqrt{63}$ as the product of an integer and another irrational square root in simplest form, we can find the largest perfect square factor of 63. In this case, it is 9.

So we can write $\sqrt{63}$ as $\sqrt{9 \cdot 7}$. Taking the square root of 9 gives us 3.

Thus, $\sqrt{63}$ can be simplified as $3\sqrt{7}$.

Therefore, $\sqrt{63}$ rewritten as the product of an integer and another irrational square root in simplest form is $\boxed{3\sqrt{7}}$.

Answer 18

what is the irrational square root ^3√81 rewritten as the product of an integer and another irrational cube root

note: you will find the option to add a cubic root symbol in the algebra (x) keyboard

Answer 19

[AI-generated answer — Bot GPT 3.5]

The cube root of 81 is equal to the number that, when multiplied by itself three times, equals 81.

To rewrite $\sqrt[3]{81}$ as the product of an integer and another irrational cube root, we can simplify it as follows:

$\sqrt[3]{81} = \sqrt[3]{27 \cdot 3} = \sqrt[3]{27} \cdot \sqrt[3]{3} = 3 \cdot \sqrt[3]{3}$.

Therefore, $\sqrt[3]{81}$ rewritten as the product of an integer and another irrational cube root is $\boxed{3\sqrt[3]{3}}$.

Answer 20

find the cube root of -8: ^3√-8

Answer 21

[AI-generated answer — Bot GPT 3.5]

The cube root of -8, denoted as $\sqrt[3]{-8}$ or $^3\sqrt{-8}$, is equal to the number that, when multiplied by itself three times, equals -8.

In this case, the cube root of -8 is -2, since $(-2)^3 = -8$.

Therefore, the cube root of -8 is $\boxed{-2}$.