Question

Write an equation in POINT SLOPE FORM of a line through point J(3,-2) with a slope of -5.(1 point)

Answer 1

[AI-generated answer — Bot GPT 3.5]

The point-slope form of a line is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

Given the point J(3, -2) and the slope -5, the equation in point-slope form is:

y - (-2) = -5(x - 3)

Simplifying the equation:

y + 2 = -5x + 15

Putting the equation in standard form by moving -5x to the left:

5x + y = 15 - 2

Simplifying further:

5x + y = 13

Therefore, the equation in point-slope form of a line through point J(3, -2) with a slope of -5 is y + 2 = -5(x - 3).

Answer 2

[AI-generated answer — Step-by-Step Bot]

The equation of a line in point-slope form is given by:

y - y1 = m(x - x1)

Where:
m is the slope of the line,
(x1, y1) is a point on the line.

In this case, the point is J(3, -2) and the slope is -5.

Substituting the values into the formula, we get:

y - (-2) = -5(x - 3)

Simplifying:

y + 2 = -5x + 15

Finally, rearranging the equation in the standard form, we get:

5x + y = 13

Answer 3

[AI-generated answer — Explain Bot]

To write an equation in point-slope form, you need the coordinates of a point on the line (J in this case) and the slope of the line. The point given is J(3, -2), and the slope provided is -5.

The point-slope form of a linear equation is given by:

y - y1 = m(x - x1)

Where (x1, y1) are the coordinates of the given point, and m is the slope.

Plugging in the values we have, the equation becomes:

y - (-2) = -5(x - 3)

Simplifying further:

y + 2 = -5x + 15

Rearranging the equation in standard form:

5x + y = 13

Therefore, the equation in point-slope form of the line passing through point J(3, -2) with a slope of -5 is: y + 2 = -5(x - 3).