To find the solutions of a quadratic equation, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Given the equation 2x^2 - 16x + 32 = 0, we can identify the coefficients as follows:
a = 2
b = -16
c = 32
Now, let's substitute these values into the quadratic formula:
x = (-( -16) ± √((-16)^2 - 4 * 2 * 32)) / (2 * 2)
Simplifying:
x = (16 ± √(256 - 256)) / 4
x = (16 ± √(0)) / 4
Since the discriminant (√(b^2 - 4ac)) is zero, it means that there is only one solution. The solutions are:
x = 16/4
x = 4
Thus, the quadratic equation 2x^2 - 16x + 32 = 0 has one solution, which is x = 4.