To find the value of c that would make both systems have the same solution, we need to compare the coefficients of the variables in the two systems.
Let's start with the first system:
4x + y = -1 -- Equation 1
x + y = 2 -- Equation 2
Now let's consider the second system:
8x + 2y = -2 -- Equation 3
-4x + cy = -8 -- Equation 4
To have the same solution for both systems, the coefficients of x and y in Equation 3 should be multiples of the coefficients of x and y in Equation 1, and the coefficients of x and y in Equation 4 should be multiples of the coefficients of x and y in Equation 2.
Comparing the coefficients, we can see that the coefficient of x in Equation 3 is 8, while the coefficient of x in Equation 1 is 4. To make them multiples, we need to double Equation 1. Similarly, the coefficient of y in Equation 3 is 2, while the coefficient of y in Equation 1 is 1. We also need to double Equation 1 to match Equation 3.
Now let's compare the coefficients in Equation 4 with those in Equation 2. The coefficient of x in Equation 4 is -4, while the coefficient of x in Equation 2 is 1. To make them multiples, we need to multiply Equation 2 by -4. The coefficient of y in Equation 4 is c, while the coefficient of y in Equation 2 is 1. So, to have the same solution, the coefficient of y in Equation 4 should also be c.
After making these adjustments, the two systems become:
8x + 2y = -2 -- Equation 3 (same as Equation 1 after doubling)
-4x + cy = -8 -- Equation 4 (same as Equation 2 after multiplying by -4)
So, to make both systems have the same solution, the value of c should be 2.