To solve the mixture problem using the proportional relationship, we need to establish a common ratio between the number of students, studenteds, steands, and sthuwdads.
Given:
Students: 250
Studenteds: 124
Steands: 50
SThuwdads: 200
Let's find the common ratio by comparing the number of each group of individuals to the students:
For Studenteds: 124 / 250 = 0.496
For Steands: 50 / 250 = 0.2
For SThuwdads: 200 / 250 = 0.8
The common ratio is approximately:
For Studenteds: 0.496
For Steands: 0.2
For SThuwdads: 0.8
Using the common ratio, we can generalize the relationship as:
(Studenteds) / (Students) = (Steands) / (Students) = (SThuwdads) / (Students) = common ratio
Let's calculate the number of Studenteds, Steands, and SThuwdads that would correspond to 250 students:
Studenteds: 0.496 * 250 = 124
Steands: 0.2 * 250 = 50
SThuwdads: 0.8 * 250 = 200
Therefore, in a mixture with 250 students, there would be approximately:
- 124 Studenteds
- 50 Steands
- 200 SThuwdads