To solve this system of equations, we will use the method of substitution.
First, let's solve one of the equations for one variable in terms of the other variable. Let's solve the second equation for x:
3x + 5y = 36
Subtract 5y from both sides:
3x = 36 - 5y
Next, divide both sides by 3 to solve for x:
x = (36 - 5y) / 3
Now, substitute the value of x in the first equation:
6((36 - 5y) / 3) - 5y = 27
Simplify the equation:
2(36 - 5y) - 5y = 27
Expand and distribute:
72 - 10y - 5y = 27
Combine like terms:
-15y + 72 = 27
Now, isolate the variable by subtracting 72 from both sides:
-15y = 27 - 72
Simplify:
-15y = -45
Finally, divide both sides by -15 to solve for y:
y = -45 / -15
Simplify:
y = 3
Now, substitute this value of y back into one of the original equations to solve for x. Let's use the second equation:
3x + 5(3) = 36
Multiply:
3x + 15 = 36
Subtract 15 from both sides:
3x = 36 - 15
Simplify:
3x = 21
Finally, divide both sides by 3 to solve for x:
x = 21 / 3
Simplify:
x = 7
Therefore, the solution to the system of equations is x = 7 and y = 3.