Question

Place the numbers in descending order.

2.3 × 10^-10;3.2 × 10^-10; 2.3 × 10^-12;2.3 × 10^-8

Answer 1

[AI-generated answer — Bot GPT 3.5]

Arranging the numbers in descending order:

3.2 × 10^-10
2.3 × 10^-10
2.3 × 10^-12
2.3 × 10^-8

Answer 2

[AI-generated answer — Step-by-Step Bot]

To arrange the numbers in descending order, start by comparing the values of the exponents.

1. 2.3 × 10^-12
2.3 × 10^-10
2.3 × 10^-8
3.2 × 10^-10

Since -12 is the smallest exponent, the number with 10^-12 should come first.

1. 2.3 × 10^-12

Next, compare the remaining numbers:

2. 2.3 × 10^-10
3.2 × 10^-10
2.3 × 10^-8

Both numbers have 10^-10 as the exponent, so compare the values before the exponent.

2. 2.3 × 10^-10
3. 3.2 × 10^-10

Finally, the number with the largest value before the exponent is:

4. 2.3 × 10^-8

So, the numbers arranged in descending order are:

2.3 × 10^-12; 2.3 × 10^-10; 3.2 × 10^-10; 2.3 × 10^-8.

Answer 3

[AI-generated answer — Explain Bot]

To place the numbers in descending order, we need to compare the values of the numbers with the exponent of 10.

Let's compare the numbers:
2.3 × 10^-10
3.2 × 10^-10
2.3 × 10^-12
2.3 × 10^-8

Comparing the exponents, we can see that -12 is the smallest, followed by -10, and then -8.

Now let's compare the coefficients (the numbers before the × 10^-x):
2.3
3.2
2.3
2.3

Since the exponents are the same (-10), we compare the coefficients. In this case, we have a tie with two numbers being 2.3.

To break the tie, we look at the remaining numbers. The remaining numbers are the smallest ones:
2.3 × 10^-12
2.3 × 10^-10

Comparing the coefficients, we can see that 2.3 is the same for both. But since 10^-12 is smaller than 10^-10, the number 2.3 × 10^-12 should come before 2.3 × 10^-10.

Finally, we have the descending order:
2.3 × 10^-12
2.3 × 10^-10
2.3 × 10^-10
2.3 × 10^-8