Column A
1. X: c.3
2. Y: b.1
3. Z: a.2
(X)N2 + (Y)H2 → (Z)NH3
Column A
1.
X:
X
2.
Y:
Y
3.
Z:
Z
Column B
a.2
b.1
c.3
1. X: c.3
2. Y: b.1
3. Z: a.2
Let's analyze each element separately:
1. Nitrogen (N):
- On the left-hand side (LHS) of the equation, there are 2 nitrogen atoms in N2.
- On the right-hand side (RHS) of the equation, there is 1 nitrogen atom in NH3.
- To balance the nitrogen atoms, X should be equal to Z.
Therefore, the correct answer for X is b. 1.
2. Hydrogen (H):
- On the LHS of the equation, there are 2 hydrogen atoms in H2.
- On the RHS of the equation, there are 3 hydrogen atoms in NH3.
- To balance the hydrogen atoms, Y should be equal to 3.
Therefore, the correct answer for Y is c. 3.
3. Ammonia (NH3):
- On the LHS of the equation, there are no ammonia molecules.
- On the RHS of the equation, there is 1 ammonia molecule.
- To balance the number of ammonia molecules, Z should be equal to 1.
Therefore, the correct answer for Z is b. 1.
Therefore, the correct matching is:
X: b. 1
Y: c. 3
Z: b. 1
Starting with the nitrogen, we have X nitrogen (N) atoms on the left side of the equation and Z nitrogen (N) atoms on the right side. The number of nitrogen atoms does not change during the reaction. Therefore, X should be equal to Z.
Next, looking at the hydrogen (H) atoms, we have 2Y hydrogen (H) atoms on the left side and 3Z hydrogen (H) atoms on the right side. To balance the hydrogen atoms, we multiply Y by 3 and Z by 2. Thus, 2Y = 3Z.
Now we can compare the options in Column B.
1. X: X
Since X should be equal to Z, we can eliminate this option as it doesn't specify the relation between X and Z.
2. Y: Y
This option states that Y is equal to itself, which doesn't provide any new information.
3. Z: Z
This option states that Z is equal to itself, which is true based on our previous explanation.
Considering the equation 2Y = 3Z, we can conclude that if Y = 2, then Z must be 3 to balance the equation.
Therefore, the correct match between the missing coefficients and the numbers of molecules is:
X: Z (option 1a. 2)
Y: 2 (option 2a. 1)
Z: 3 (option 3c. 3)