A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point) Responses 7.5 N 7.5 N 0.01 N 0.01 N 6.5 N 6.5 N 1 N

Step-by-Step Bot Step-by-Step Bot answered
8 months ago

To find the force exerted by the floor on the ball, we can use Newton's second law of motion:

Force (F) = mass (m) × acceleration (a)

Given:
Mass of the ball (m) = 0.1 kilograms
Acceleration (a) = 10 meters per second squared

Substituting the values into the formula:

F = 0.1 kg × 10 m/s^2
F = 1 N

Therefore, the force exerted by the floor on the ball is 1 N.

Bot GPT 3.5 Bot GPT 3.5 answered
8 months ago

To find the force exerted by the floor on the south end of the court, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

First, we need to convert the mass of the ball from kilograms to grams, since acceleration is given in meters per second squared.

0.1 kilograms * 1000 grams/kilogram = 100 grams

Now, we can calculate the force:

Force = mass * acceleration
Force = 100 grams * 10 meters per second squared
Force = 1000 grams * meters per second squared
Force = 1000 grams * 1 meter per second squared
Force = 1000 grams*m/s^2

Therefore, the force exerted by the floor on the ball is 1000 grams*m/s^2, or 1 Newton (1 N).

Explain Bot Explain Bot answered
8 months ago

To determine the force exerted by the floor on the south end of the court, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

First, let's calculate the initial velocity of the tennis ball when it hits the floor. We are given that the racket was traveling at 65 kilometers per hour. To convert this to meters per second, we divide by 3.6 (because 1 kilometer per hour equals 1 kilometer per 3.6 seconds). Therefore, the initial velocity of the tennis ball is 65 km/h / 3.6 = 18.06 m/s.

Next, we need to calculate the time it takes for the ball to travel from the north end to the south end of the court. In order to find this, we can use the kinematic equation:

v = u + at

where v is the final velocity (0 m/s), u is the initial velocity (18.06 m/s), a is the acceleration (-10 m/s^2), and t is the time.

Rearranging the equation to solve for t:

t = (v - u) / a

t = (0 - 18.06) / -10

t ≈ 1.806 seconds

Now let's calculate the distance traveled by the ball. We can use the formula:

s = ut + (1/2)at^2

where s is the distance, u is the initial velocity, t is the time, and a is the acceleration.

s = 18.06 * 1.806 + (1/2)(-10)(1.806)^2

s ≈ 16.39 meters

Finally, we can calculate the force exerted by the floor by multiplying the mass of the ball (0.1 kg) by the acceleration (10 m/s^2). This gives us:

F = m * a

F = 0.1 * 10

F = 1 N

Therefore, the answer is 1 N.

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