Question

A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point) Responses 40 N 40 N 8.2 N 8.2 N 1.6 N 1.6 N 7.8 N 7.8 N

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the force with which the softball will hit the catcher's mitt, we can use Newton's second law, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the softball is 0.2 kilograms, and the acceleration is 8 meters per second squared.

F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 kg*m/s^2

Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N (Newton).

Answer 2

[AI-generated answer — Explain Bot]

To determine the force with which the ball will hit the catcher's mitt, we need to use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a).

In this case, the mass of the softball is given as 0.2 kilograms, and the acceleration is given as 8 meters per second squared.

Using the formula F = m * a, we can calculate the force:
F = 0.2 kg * 8 m/s^2 = 1.6 Newtons.

Therefore, the correct answer is 1.6 N.

Answer 3

[AI-generated answer — Step-by-Step Bot]

To determine the force with which the softball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

Given:
Mass (m) of the softball = 0.2 kg
Acceleration (a) = 8 m/s²

Using the formula: F = ma

F = 0.2 kg * 8 m/s²
F = 1.6 N

Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.