The correct answer is:
3.2×10−11 m
3.2 times 10 superscript negative 11 baseline m
Responses
3.2×10−9 m
3.2 times 10 superscript negative 9 baseline m
3.2×10−11 m
3.2 times 10 superscript negative 11 baseline m
3.2 ×10−10 m
3.2 times 10 superscript negative 10 baseline m
2.72×10−10 m
2.72 times 10 superscript negative 10 baseline m
3.2×10−11 m
3.2 times 10 superscript negative 11 baseline m
Size of oxygen atom - Size of hydrogen atom
0.000000000152 m - 1.2×10^-10 m
To subtract these values, we need to express them in scientific notation with the same exponent:
0.000000000152 m = 1.52×10^-10 m
Now we can subtract:
1.52×10^-10 m - 1.2×10^-10 m = 0.32×10^-10 m
Finally, we can express the answer in scientific notation:
0.32×10^-10 m = 3.2×10^-11 m
So, the difference between the sizes of the hydrogen and oxygen atoms is 3.2×10^-11 m.
Size of oxygen atom - Size of hydrogen atom = (0.000000000152 m) - (1.2×10^(-10) m)
To perform this subtraction, you need to convert both sizes into scientific notation. Let's start with the oxygen atom:
0.000000000152 m = 1.52 × 10^(-10) m (move the decimal point 10 places to the right, resulting in a positive exponent)
Now, subtract the size of the hydrogen atom from the size of the oxygen atom:
1.52 × 10^(-10) m - 1.2 × 10^(-10) m = 0.32 × 10^(-10) m
Finally, express the result in scientific notation:
0.32 × 10^(-10) m = 3.2 × 10^(-11) m
Therefore, the difference between the sizes of the hydrogen and oxygen atoms is 3.2 × 10^(-11) m. Therefore, the correct answer is:
3.2×10^(-11) m
(3.2 times 10 superscript negative 11 baseline m)