The size of a hydrogen atom is about 1.2×10−10 m across. The size of an oxygen atom is 0.000000000152 m across. What is the difference between the sizes of these atoms in scientific notation?(1 point)

Responses

3.2×10−9 m
3.2 times 10 superscript negative 9 baseline m

3.2×10−11 m
3.2 times 10 superscript negative 11 baseline m

3.2 ×10−10 m
3.2 times 10 superscript negative 10 baseline m

2.72×10−10 m
2.72 times 10 superscript negative 10 baseline m

Bot GPT 3.5 Bot GPT 3.5 answered
8 months ago

The correct answer is:

3.2×10−11 m
3.2 times 10 superscript negative 11 baseline m

Step-by-Step Bot Step-by-Step Bot answered
8 months ago

To find the difference between the sizes of these atoms, we subtract the size of the hydrogen atom from the size of the oxygen atom:

Size of oxygen atom - Size of hydrogen atom

0.000000000152 m - 1.2×10^-10 m

To subtract these values, we need to express them in scientific notation with the same exponent:

0.000000000152 m = 1.52×10^-10 m

Now we can subtract:

1.52×10^-10 m - 1.2×10^-10 m = 0.32×10^-10 m

Finally, we can express the answer in scientific notation:

0.32×10^-10 m = 3.2×10^-11 m

So, the difference between the sizes of the hydrogen and oxygen atoms is 3.2×10^-11 m.

Explain Bot Explain Bot answered
8 months ago

To find the difference between the sizes of the hydrogen and oxygen atoms, you need to subtract the size of the hydrogen atom from the size of the oxygen atom:

Size of oxygen atom - Size of hydrogen atom = (0.000000000152 m) - (1.2×10^(-10) m)

To perform this subtraction, you need to convert both sizes into scientific notation. Let's start with the oxygen atom:

0.000000000152 m = 1.52 × 10^(-10) m (move the decimal point 10 places to the right, resulting in a positive exponent)

Now, subtract the size of the hydrogen atom from the size of the oxygen atom:

1.52 × 10^(-10) m - 1.2 × 10^(-10) m = 0.32 × 10^(-10) m

Finally, express the result in scientific notation:

0.32 × 10^(-10) m = 3.2 × 10^(-11) m

Therefore, the difference between the sizes of the hydrogen and oxygen atoms is 3.2 × 10^(-11) m. Therefore, the correct answer is:

3.2×10^(-11) m
(3.2 times 10 superscript negative 11 baseline m)

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