Question

A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)%0D%0AResponses%0D%0A%0D%0A1 N%0D%0A1 N%0D%0A%0D%0A7.5 N%0D%0A7.5 N%0D%0A%0D%0A6.5 N%0D%0A6.5 N%0D%0A%0D%0A0.01 N

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the force exerted by the floor on the ball, we can use Newton's second law of motion: force = mass * acceleration.

Given:
Mass of the ball (m) = 0.1 kg
Acceleration (a) = 10 m/s^2

Using the formula:

Force = Mass * Acceleration
= 0.1 kg * 10 m/s^2
= 1 N

Therefore, the floor on the south end of the court exerted 1 N of force on the ball.

Answer 2

[AI-generated answer — Step-by-Step Bot]

To find the force exerted by the floor on the ball, we can use Newton's second law of motion:

Force = Mass * Acceleration

First, let's convert the racket's speed from km/h to m/s:
65 km/h * (1000 m / 1 km) * (1 h / 3600 s) = 18.06 m/s

Now let's calculate the initial velocity of the ball when it leaves the racket. Assuming the ball is at rest initially, the initial velocity is the same as the racket's speed:

Initial velocity of the ball = 18.06 m/s

Next, let's calculate the time it takes for the ball to hit the floor on the south end of the court. We can use the equation:

Final velocity = Initial velocity + (Acceleration * Time)

The final velocity is 0 m/s because the ball hits the floor and comes to a stop. So, rearranging the equation, we have:

Time = (Final velocity - Initial velocity) / Acceleration

Time = (0 m/s - 18.06 m/s) / (10 m/s^2) = -1.81 s

Since time cannot have a negative value, we discard the negative sign. Therefore, the time it takes for the ball to hit the floor is 1.81 seconds.

Using Newton's second law of motion, we can now calculate the force exerted by the floor on the ball:

Force = Mass * Acceleration

Force = 0.1 kg * 10 m/s^2 = 1 N

So, the floor on the south end of the court exerts a force of 1 N on the ball.

Answer 3

[AI-generated answer — Explain Bot]

To find the force exerted by the floor on the south end of the court, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

First, let's calculate the initial velocity of the tennis ball. Since the ball is hit by the racket, it will have the same velocity as the racket. However, the velocity needs to be converted from kilometers per hour (km/h) to meters per second (m/s).

Given:
Racket velocity (v) = 65 km/h
Ball mass (m) = 0.1 kg
Ball acceleration (a) = 10 m/s^2

Convert the racket velocity from km/h to m/s:
v = 65 km/h * (1000 m / 1 km) * (1 h / 3600 s) ≈ 18.1 m/s

Now we can calculate the force using the formula F = m * a:
F = 0.1 kg * 10 m/s^2 = 1 N

Therefore, the force exerted by the floor on the south end of the court is 1 newton (N).