To determine which system the point (0,-2) is a solution to, we can substitute the x and y values of the point into each system equation and see which equations are satisfied.
For option a:
x + y = 2
Substituting x = 0 and y = -2:
0 + (-2) β 2
-x + 2y = 16
Substituting x = 0 and y = -2:
0 + 2(-2) β 16
Therefore, option a is not the correct system.
For option b:
-5x = y - 3
Substituting x = 0 and y = -2:
-5(0) = (-2) - 3
0 = -2 - 3
0 = -5
3x - 8y = 24
Substituting x = 0 and y = -2:
3(0) - 8(-2) β 24
Therefore, option b is not the correct system.
For option c:
-4x + y = 6
Substituting x = 0 and y = -2:
-4(0) + (-2) = 6
-2 = 6
-5x - y = 21
Substituting x = 0 and y = -2:
-5(0) - (-2) β 21
Therefore, option c is not the correct system.
For option d:
-5x + y = -2
Substituting x = 0 and y = -2:
-5(0) + (-2) = -2
-2 = -2
-3x + 6y = -12
Substituting x = 0 and y = -2:
-3(0) + 6(-2) = -12
-12 = -12
Therefore, option d is the correct system.
Therefore, the point (0,-2) is a solution to the system -5x + y = -2 and -3x + 6y = -12.