To determine the system of equations that the point (0,-2) is a solution to, we can substitute the values x = 0 and y = -2 into each equation and see which equations are satisfied.
For the first equation, x + y = 2:
0 + (-2) = 2
-2 = 2
This equation is not satisfied by the point (0,-2).
For the second equation, -x + 2y = 16:
-(0) + 2(-2) = 16
-4 = 16
This equation is not satisfied by the point (0,-2).
For the third equation, x + y = 2 and -x + 2y = 16:
0 + (-2) = 2
-2 = 2
-(0) + 2(-2) = 16
-4 = 16
Both equations are not satisfied by the point (0,-2).
For the fourth equation, -5x = y - 3:
-5(0) = (-2) - 3
0 = -2 - 3
0 = -5
This equation is not satisfied by the point (0,-2).
For the fifth equation, 3x - 8y = 24:
3(0) - 8(-2) = 24
16 = 24
This equation is not satisfied by the point (0,-2).
For the sixth equation, -5x = y - 3 and 3x - 8y = 24:
-5(0) = (-2) - 3
0 = -2 - 3
0 = -5
3(0) - 8(-2) = 24
16 = 24
Both equations are not satisfied by the point (0,-2).
For the seventh equation, -4x + y = 6:
-4(0) + (-2) = 6
-2 = 6
This equation is not satisfied by the point (0,-2).
For the eighth equation, -5x - y = 21:
-5(0) - (-2) = 21
2 = 21
This equation is not satisfied by the point (0,-2).
For the ninth equation, -4x + y = 6 and -5x - y = 21:
-4(0) + (-2) = 6
-2 = 6
-5(0) - (-2) = 21
2 = 21
Both equations are not satisfied by the point (0,-2).
For the tenth equation, -5x + y = -2:
-5(0) + (-2) = -2
-2 = -2
This equation is satisfied by the point (0,-2).
For the eleventh equation, -3x + 6y = -12:
-3(0) + 6(-2) = -12
-12 = -12
This equation is satisfied by the point (0,-2).
Therefore, the point (0,-2) is a solution to the system of equations:
-5x + y = -2
-3x + 6y = -12