To find the missing number in the quadratic equation, we can start by using the fact that the solutions of the quadratic equation are given by the formula:
x = (-b ± sqrt(b^2 - 4ac)) / (2a)
In the equation x² - 14x + ______ = 0, the coefficient of the x² term is 1 (since it is written as x²), the coefficient of the x term is -14, and the constant term is the missing number. We can plug in the known values for the solutions, which are 6 and 8, and use the fact that the solutions are equal to x:
6 = (-(-14) ± sqrt((-14)^2 - 4(1)(______))) / (2(1))
8 = (-(-14) ± sqrt((-14)^2 - 4(1)(______))) / (2(1))
Simplifying these equations, we get:
6 = (14 ± sqrt(196 - 4(1)(______))) / 2
8 = (14 ± sqrt(196 - 4(1)(______))) / 2
To find the missing number, we need to solve for it. Let's solve the first equation for the missing number:
6 = (14 ± sqrt(196 - 4(1)(______))) / 2
Multiply both sides by 2:
12 = 14 ± sqrt(196 - 4(1)(______))
Subtract 14 from both sides:
-2 = ± sqrt(196 - 4(1)(______))
Square both sides to remove the square root:
(-2)^2 = (sqrt(196 - 4(1)(______)))^2
4 = 196 - 4(1)(______)
Simplify:
4 = 196 - 4(______)
4 = 196 - 4(______)
4 = 196 - 4______
4 = 196 - ______
4 = 196 - ______
Subtract 196 from both sides:
-192 = -______
Therefore, the missing number is 192. So, the quadratic equation is:
x² - 14x + 192 = 0