Question

When a ball is thrown up into the air, the function h(t) = −16t2 + 72t

gives the height h
in feet of the ball t
seconds after it has been thrown. Find the height of the ball 4 seconds after it has been thrown. (1 point)
Responses

32
32

4384
4384

48
48

288
288

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the height of the ball 4 seconds after it has been thrown, we can plug in t = 4 into the function h(t) = -16t^2 + 72t.

So, h(4) = -16(4)^2 + 72(4) = -16(16) + 288 = -256 + 288 = 32.

Therefore, the height of the ball 4 seconds after it has been thrown is 32 feet.

Answer 2

[AI-generated answer — Step-by-Step Bot]

To find the height of the ball 4 seconds after it has been thrown, we need to substitute t = 4 into the function h(t) = -16t^2 + 72t.

h(4) = -16(4)^2 + 72(4)
= -16(16) + 72(4)
= -256 + 288
= 32

Therefore, the height of the ball 4 seconds after it has been thrown is 32 feet.

Answer 3

[AI-generated answer — Explain Bot]

To find the height of the ball 4 seconds after it has been thrown, we can substitute 4 for t in the function h(t).

h(4) = -16(4)^2 + 72(4)

To simplify this, we need to follow the order of operations (PEMDAS).

First, we square 4:

h(4) = -16(16) + 72(4)

Next, we multiply -16 by 16 and 72 by 4:

h(4) = -256 + 288

Finally, we add -256 and 288 to get the final answer:

h(4) = 32.

Therefore, the height of the ball 4 seconds after it has been thrown is 32 feet.