Question

Which of the following values could be used for x and would cause the following relation to NOT be a function?

{(2,3), (-2,6), (3,-4), (x, 2), (5,-9)}



Responses

x=-4
x=-4

x=6
x=6

x=0
x=0

x=3

Answer 1

[AI-generated answer — Bot GPT 3.5]

x=3

Answer 2

[AI-generated answer — Step-by-Step Bot]

To determine which value of x would cause the relation to NOT be a function, we need to check if there are any repeated x-values in the relation.

In the given relation, we have the following values of x: 2, -2, 3, x, and 5.

To find the value of x that could cause the relation to NOT be a function, we need to see if any of these values appear more than once in the relation.

From the given relation, we see that x=-4 and x=6 are NOT present as values of x in the relation. This means that we can use x=-4 or x=6 as values for x and the relation will still be a function.

However, x=0 and x=3 are already present as values of x in the relation. Therefore, using x=0 or x=3 as values for x would cause the relation to have repeated x-values and it would NOT be a function.

So, the values of x that would cause the given relation to NOT be a function are x=0 and x=3.

Answer 3

[AI-generated answer — Explain Bot]

To determine whether the given relation is a function, we need to check if each x-value has a unique y-value.

In this case, the relation {(2,3), (-2,6), (3,-4), (x, 2), (5,-9)} would not be a function if there is any repeated x-value with different y-values.

Let's consider each value of x from the given options:

1) x = -4:
To check if (-4, y) has a unique y-value, we need to see if (-4, y) appears anywhere else in the relation. In this case, (-4, 6) already exists in the relation. Therefore, x = -4 would cause the relation to not be a function.

2) x = 6:
Similarly, to check if (6, y) has a unique y-value, we need to see if (6, y) appears anywhere else in the relation. In this case, (6, 2) already exists in the relation. Therefore, x = 6 would cause the relation to not be a function.

3) x = 0:
To check if (0, y) has a unique y-value, we need to see if (0, y) appears anywhere else in the relation. In this case, (0, 2) exists in the relation only once. Therefore, x = 0 would not cause the relation to not be a function.

4) x = 3:
To check if (3, y) has a unique y-value, we need to see if (3, y) appears anywhere else in the relation. In this case, (3, -4) already exists in the relation. Therefore, x = 3 would cause the relation to not be a function.

So, out of the options given, both x = -4 and x = 6 would cause the relation to not be a function.